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The ratio of the length of the parallel sides of a trapezium is 3:2. The shortest distance between them is 15 cm. If the area of the trapezium is 450 cm2, the sum of the length of the parallel sides is

A15 cm

B36 cm

C42 cm

D60 cm

Answer:

D. 60 cm

Read Explanation:

.Area of the trapezium =12×\frac{1}{2}\times(sumof parallel sides) × altitude

450=12(3x+2x)×15450=\frac{1}{2}(3x+2x)\times{15}

5x=450×215=60cm5x=\frac{450\times{2}}{15}=60cm

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