Question

What is the average of the squares of the first 10 natural numbers?

• A. 38.5
• B. 39
• C. 40
• D. 42

Answer 1

Answer:

A. 38.5

The sum of the squares of the first n natural numbers = (n)(n+1(2n+1)/6 Average of the squares of the first 10 natural numbers = (10+1)×(10×2+1)/6 = (11×21)/6 = 38.5