Question:
What is the average of the squares of the first 10 natural numbers?
A38.5
B39
C40
D42
Answer:
A. 38.5
Explanation:
The sum of the squares of the first n natural numbers = (n)(n+1(2n+1)/6 Average of the squares of the first 10 natural numbers = (10+1)×(10×2+1)/6 = (11×21)/6 = 38.5