What is the average of the squares of the first 10 natural numbers?
A38.5
B39
C40
D42
Answer:
A. 38.5
Read Explanation:
The sum of the squares of the first n natural numbers = (n)(n+1(2n+1)/6
Average of the squares of the first 10 natural numbers
= (10+1)×(10×2+1)/6
= (11×21)/6
= 38.5
