Challenger App

No.1 PSC Learning App

1M+ Downloads

23+23+23+23 2^3+2^3+2^3+2^3 ന് തുല്യമായതേത്?

A2⁵

B2⁸¹

C2¹²

D2¹⁶

Answer:

A. 2⁵

Read Explanation:

23+23+23+232^3+2^3+2^3+2^3

232^3 പൊതുവായി എടുത്താൽ

=(1+1+1+1)23=(1+1+1+1)2^3

=4×23=4\times2^3

=22×23= 2^2\times2^3

=22+3=25=2^{2+3}=2^5

am×am=am+n\because{a^m\times{a^m}=a^{m+n}}

am+am=2×ama^m+a^m=2\times{a^m}

 

 

 

 


Related Questions:

image.png

814÷729(2x)=94x81^{-4}\div 729^{(2-x)}=9^{4x} എങ്കിൽ x =

image.png

10×(23)2×(53)2=\sqrt{10\times{\sqrt{(2^3)^2}}\times\sqrt{(5^3)^2}}=