A5/4
B3/7
C2/6
D7/8
Answer:
Related Questions:
112+3/4+1/4+1/2=1\frac12 + 3/4 + 1/4 + 1/2 =121+3/4+1/4+1/2=
[(5/6)5×(4/3)−4]÷[(5/6)6×(3/4)4]=?[{(5/6)^5\times(4/3)^{-4}}]\div[{(5/6)^6\times(3/4)^4}]=?[(5/6)5×(4/3)−4]÷[(5/6)6×(3/4)4]=?
x=2, y= -2 ആയാൽ Xx+Yy=X^x+Y^y=Xx+Yy=
