Challenger App

No.1 PSC Learning App

1M+ Downloads
In an examination A obtains 48% of full marks and B obtain 33% of full marks. Together they get 567 marks. Find the full marks :

A600

B800

C700

D900

Answer:

C. 700

Read Explanation:

Let the full marks be x "A" obtains 48% of full marks and "B" obtains 33% of full marks. Together they obtain (48+33) 81% of full marks which is 567 A/Q 81% of x = 567 => 81x/100 = 567 => x = 567 × 100/81 => x = 700


Related Questions:

A number is divided into two parts in such a way that 80% of 1st part is 3 more than 60% of 2nd part and 80% of 2nd part is 6 more than 90% of the 1st part. Then the number is-
The sum of the number of boys and girls in a school is 300.If the number of boys is x, then the number of girls becomes x% of the total number of students. How many girls are there in the school?
What is 15% of 82?
In an examination a student has to get 40% of total marks to pass. In one paper he gets 85 out of 200 and in the second paper he gets 70 out of 150. How many marks should he get out of 250 marks in the third paper to pass in the examination?
ഒരു സംഖ്യയുടെ 50 ശതമാനത്തോട് 10 കൂട്ടിയാൽ 300 ലഭിക്കും എങ്കിൽ സംഖ്യ ഏത്?