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വീട്ടിൽ നിന്നും രാമു 3 Km/hr വേഗതയിൽ സഞ്ചരിച്ചാൽ സ്‌കൂളിലെത്താൻ 25 മിനിറ്റ് വൈകും. 4 Km/hr വേഗതയിൽ സഞ്ചരിച്ചാൽ 15 മിനിറ്റ് നേരത്തെ സ്‌കൂളിലെത്തും. എങ്കിൽ രാമുവിന്റെ വീട്ടിൽ നിന്നും സ്‌കൂൾ എത്ര അകലെയാണ്?

A20km

B12 km

C8 km

D32 km

Answer:

C. 8 km

Read Explanation:

$$ദൂരം=$\frac{S_1\times{S_2}}{S_1-S_2}\times{T_d}$

$S_1=3,S_2=4,T_d=25+15=40/60 hr$

$\implies\frac{3\times4}{4-3}\times\frac{40}{60}$

$=8$

 


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