App Logo

No.1 PSC Learning App

1M+ Downloads

ABCD is a rectangle, where AB = 4 cm and AD = 2 cm. Two arcs are drawn of radius AD and BC respectively. What is the area of the shaded region?

image.png

A4π4 – π cm^2$$

B8π8 – π cm^2$$

C42π4 – 2π cm^2$$

D82π8 – 2π cm^2$$

Answer:

82π8 – 2π cm^2$$

Read Explanation:

Given:

⇒ Length of the rectangle = 4 cm

⇒ Breadth of the rectangle = 2 cm

Calculation:

∴ Area of the rectangle = 4×2=8cm24\times{2}=8cm^2

⇒ Area of the arc having radius AD,

14×π×22⇒\frac{1}{4}\times{π}\times{22}

πcm2⇒πcm^2

⇒ Area of the arc having radius BC,

14×π×22⇒\frac{1}{4}\times{π}\times{22}

πcm2⇒πcm^2

∴ Area of the shaded region,

⇒8-2π cm2cm^2


Related Questions:

The parallel sides of a trapezium are in a ratio 2 : 3 and their shortest distance is 12 cm. If the area of the trapezium is 480 sq.cm., the longer of the parallel sides is of length :
In ΔABC, right angled at B, BC = 15 cm and AB = 8 cm. A circle is inscribed in ΔABC. The radius of the circle is:
2½ മീറ്റർ നീളവും 1 മീറ്റർ വീതിയുമുള്ള ഒരു ടാങ്കിൽ 10000 ലിറ്റർ വെള്ളം കൊള്ളും എങ്കിൽ ടാങ്കിന്റെ ഉയരം എത്ര ?
If the external angle of a regular polygon is 18°, then the number of diagonals in this polygon is:
The perimeter of a rhombus is 40 m and its height is 5 m. Its area is :